## Reg. Geometry Unit 1 Test Review Solutions September 19, 2013

Posted by Ms. Miller in Uncategorized.

Note: These are the answers to the Regular Geometry Test Review.

Proof #1:

 1. Given equation 2. Dist. prop. 3. $3x-13=3$ 3. Subtr. prop. = 4. $3x=16$ 4. Add. prop. = 5. $x=\frac{16}{3}$ 5. Div. prop. =
Proof #2:

 1. $7x+11=3x-5$ 1. Given equation 2. $4x+11=-5$ 2. Subtr. prop. = 3. $4x=-16$ 3. Add. prop. = 4. $x=-4$ 4. Div. prop. =
1. A 2. $m=\frac{-6}{4}=\frac{-3}{2}$
3. $\frac{a-17}{2-4}=6$
$a-17=-12$
$a=5$
4. $-4y=-5x+10$
$y=\frac{-5}{-4}x+\frac{10}{-4}$
$m=\frac{5}{4}$
5. $y+3=-2(x-7)$
6. $y-0=3(x+2)$
$y=3x+6$
7. $y-1=\frac{2}{3}(x-3)$
8. perpendicular slope: $m=\frac{1}{3}$,
therefore C
9.
10. $\overrightarrow{}TW$ 11. collinear; coplanar
12. $2\frac{1}{4}"$; $6.1 \mathrm{cm}$ 13. $6$
14. omit 15. omit
16. $15\sqrt{2}$ 17. $5\sqrt{3}=\sqrt{(5)(5)(3)}=\sqrt{75}$
18. $c^2=8^2+14^2$
$c^2=260$
$c=\sqrt{260}=2\sqrt{65}$
19. $a^2+5^2=18^2$
$a^2=299$
$a=\sqrt{299}$
20. $7$ (Pythagorean triple) 21. $LS^2+5^2=10^2$
$LS^2=75$
$LS=\sqrt{75}=5\sqrt{3}$
22. $(\frac{-1+3}{2},\frac{7-4}{2})=(1,\frac{3}{2})$ 23. $\frac{2+y}{2}=0$
$y=-2$
24. $d=\sqrt{(7-3)^2+(1+1)^2}=\sqrt{20}=2\sqrt{5}$
25. $d=\sqrt{(2-1)^2+(-7-7)^2}=\sqrt{197}$
26. $d=\sqrt{(-3-4)^2+(9-0)^2}$
$\sqrt{130}\approx 11.4$
27. $(7,11)$