## PAP Unit 1 Test Review Solutions September 19, 2013

Posted by Ms. Miller in Geometry.

Note: These are the answers to the PAP Test Review.

Proof #1:

 1. Given equation 2. Dist. prop. 3. $3x-13=3$ 3. Subtr. prop. = 4. $3x=16$ 4. Add. prop. = 5. $x=\frac{16}{3}$ 5. Div. prop. =
Proof #2:

 1. $7x+11=3x-5$ 1. Given equation 2. $4x+11=-5$ 2. Subtr. prop. = 3. $4x=-16$ 3. Add. prop. = 4. $x=-4$ 4. Div. prop. =
1. C 2. $m=\frac{-6}{4}=\frac{-3}{2}$
3. $m=\frac{0-b}{3b-0}=\frac{-b}{3b}=-\frac{1}{3}$ 4. $\frac{a-17}{2-4}=6$
$a-17=-12$
$a=5$
5. $-4y=-5x+10$
$y=\frac{-5}{-4}x+\frac{10}{-4}$
$m=\frac{5}{4}$
6. $y+3=-2(x-7)$
7. $y-0=3(x+2)$
$y=3x+6$
8. $y-1=\frac{2}{3}(x-3)$
9. perpendicular slope: $m=\frac{1}{3}$,
therefore C
10.
11. $\overrightarrow{}TW$ 12. collinear; coplanar
13. $2\frac{1}{4}"$; $6.1 \mathrm{cm}$ 14. $6$
15. omit 16. omit
17. $15\sqrt{2}$ 18. $5\sqrt{3}=\sqrt{(5)(5)(3)}=\sqrt{75}$
19. $c^2=8^2+14^2$
$c^2=260$
$c=\sqrt{260}=2\sqrt{65}$
20. $a^2+5^2=18^2$
$a^2=299$
$a=\sqrt{299}$
21. $7$ (Pythagorean triple) 22. $LS^2+5^2=10^2$
$LS^2=75$
$LS=\sqrt{75}=5\sqrt{3}$
23. $(\frac{-1+3}{2},\frac{7-4}{2})=(1,\frac{3}{2})$ 24. $\frac{2+y}{2}=0$
$y=-2$
25. $(\frac{a+a-6}{2},\frac{b+3b}{2})=(\frac{2a-6}{2},\frac{4b}{2})$
$=(a-3,2b)$
26. $(7,11)$
27. $d=\sqrt{(7-3)^2+(1+1)^2}=\sqrt{20}=2\sqrt{5}$
28. $d=\sqrt{(2-1)^2+(-7-7)^2}=\sqrt{197}$
29. $C(-3,4)$ 30. $d=\sqrt{(-3-4)^2+(9-0)^2}$
$\sqrt{130}\approx 11.4$
31. $d=\sqrt{(2a-3a)^2+(3b-4b)^2}=\sqrt{(-a)^2+(-b)^2}$
$=\sqrt{a^2+b^2}$